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1. This diamond with n = 3 prints its widest row twice. Which part of the program is the bug? ``

python
n = 3
for i in range(n):
    print(" " * (n - 1 - i) + "*" * (2 * i + 1))
for i in range(n - 1, -1, -1):
    print(" " * (n - 1 - i) + "*" * (2 * i + 1))

``

The bottom loop starts at n - 1, so the widest row is printed a second timeThe top loop should stop at range(n - 1), not at range(n)The star count 2 * i + 1 should be 2 * iThe spaces should be n - i, which adds one space to every row

2. What does this print? ``

python
n = 3
total = 0
for i in range(n):
    for j in range(2 * i + 1):
        total += 1
print(total)

``

96512

3. A pyramid with n = 4 should have 7 stars on its bottom row, but it prints 6. The star loop is: ``

python
for j in range(2 * i):
    print("*", end="")

`` Which change fixes the star count?

range(2 * i + 2)range(2 * i + 1)range(2 * i - 1)range(i)

4. This program should print a pyramid of three rows, but it prints a fourth row. ``

python
n = 3
for i in range(n + 1):
    print(" " * (n - 1 - i) + "*")

`` What causes the extra row?

print cannot start a line with a space, so the first row is wrong" " * (n - 1 - i) raises an error on the last row, which stops the programThe loop runs i from 0 to 3, so the last row has a space count of -1; " " * -1 is an empty string, and the star lands at column 0The variable n is 3, which the * operator does not accept for a string

5. Put the five steps of the pattern-debugging method in order.

Use the arrows to put the steps in order.

1.Check the first and last rows by hand
2.Compare the output with the picture, one line at a time
3.Change one thing, run again and compare
4.Draw the picture you want for a small n, and count the rows
5.Print the counts for each row before the symbols

Pattern debugging in Python