Gas station in Python

Questions 1 to 5 of 6

1. 1. In the gas station scan, the running balance goes below zero at station i. Which station does the scan try as the next start?

   Station i, the one that just failedStation 0, so the scan begins again from the first stationStation n - 1, the last station on the circleStation i + 1
2. 2. What does this code print? ``python def no_reset(gas, cost): n = len(gas) total = 0 tank = 0 start = 0 for i in range(n): diff = gas[i] - cost[i] total += diff tank += diff if tank < 0: start = i + 1 if total < 0: return -1 return start % n print(no_reset([1, 2, 3, 4, 5], [3, 4, 5, 1, 2])) ``

   423-1
3. 3. Why does can_complete_circuit check total < 0 before it returns start?

   The total is the number of stations the car can pass before refuellingThe scan only sets start when the total is positive, so a negative total leaves start unsetThe total shows which station has the most gas, and that station is the startA negative total means the fuel runs short over one full lap, so no start can finish and the answer is -1
4. 4. True or False: the start that the scan returns is the only station that can finish the lap.

   False, because gas [2, 1] with cost [1, 1] lets both station 0 and station 1 finish the lap, and the scan returns only 0True, because the proof shows that only one station can have a non-negative running balance
5. 5. True or False: the brute-force check needs % n to wrap the trip around the circle.

   False, because the loop runs only n steps, so the index never passes the end of the listTrue, because without % n the index s + k runs past the end of the list when the trip wraps, and Python raises an IndexError