Grouping with dicts

Questions 1 to 5 of 6

1. 1. What does this program print? ``python words = ['kiwi', 'fig', 'plum', 'apple', 'date'] groups = {} for w in words: groups.setdefault(len(w), []).append(w) print(sorted(groups.items()), groups.get(4)) ``

   [(4, ['kiwi', 'plum', 'date']), (3, ['fig']), (5, ['apple'])] ['kiwi', 'plum', 'date'][(3, ['fig']), (4, ['kiwi', 'plum', 'date']), (5, ['apple'])] None[(3, ['fig']), (4, ['kiwi', 'plum', 'date']), (5, ['apple'])] ['kiwi', 'plum', 'date'][(3, ['fig']), (4, ['kiwi']), (5, ['apple'])] ['kiwi']
2. 2. Which line adds a record to its key's list the first time the key appears and on every later time, without losing the records already added?

   groups[key] = [record]groups.get(key).append(record)groups[key] = []groups.setdefault(key, []).append(record)
3. 3. What does this program print? ``python orders = {} rows = [('ana', 'book'), ('ana', 'lamp')] for name, item in rows: orders[name] = [item] print(orders) ``

   {'ana': ['book', 'lamp']}{'ana': ['lamp']}{'ana': ['book']}KeyError: 'ana'
4. 4. Which dict method returns the value for a key, or stores a default value under that key and returns it when the key is missing? Give the method name.

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5. 5. If you call get on a key that is not in the dict, then call append on the result, which exception does Python raise? Give its name.

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