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1. What does this program print? ``

cpp
#include <iostream>

void print_row(int width, int field) {
    int pad = (field - width) / 2;
    for (int i = 0; i < pad; ++i) std::cout << ' ';
    for (int i = 0; i < width; ++i) std::cout << '*';
    std::cout << '\n';
}

int main() {
    print_row(4, 7);
    print_row(2, 5);
}

``

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2. What does this program print? ``

cpp
#include <iostream>

void print_row(int width, int field) {
    int pad = (field - width) / 2;
    for (int i = 0; i < pad; ++i) std::cout << ' ';
    for (int i = 0; i < width; ++i) std::cout << '*';
    std::cout << '\n';
}

void print_arrow(int head_rows, int shaft_rows, int shaft_width) {
    const int field = 2 * head_rows - 1;
    for (int row = 0; row < head_rows; ++row) print_row(1 + 2 * row, field);
    for (int row = 0; row < shaft_rows; ++row) print_row(shaft_width, field);
}

int main() {
    print_arrow(3, 1, 1);
}

``

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3. The hourglass program loops over its rows with for (int row = 0; row < 2 * half; ++row). What goes wrong with this line?

Nothing, the output is the sameThe top row is printed twiceThe bottom row is missing, because the last row is 2 * half and the loop stops before itThe middle row has no stars

4. The cross program marks a cell with (row == mid) || (col == mid). Why is || the right operator here?

Because || is a faster test than &&A cell is on the cross when it is in the middle row or in the middle column, so either test is enoughBecause || makes both arms twice as thickBecause both tests must be true at the same time before a cell is starred

5. In pad = (field - width) / 2, the / is ___ division, which throws away the fraction.

Type your answer.

Shapes