Script basics

Questions 1 to 5 of 9

1. 1. Put these steps in the order you do them to write and run the first script in the lesson.

   Use the arrows to put the steps in order.

   1. 1.Run it with bash hello.sh↑↓
   2. 2.Read the printed line hello Asha↑↓
   3. 3.Add the lines name="Asha" and echo "hello $name"↑↓
   4. 4.Create hello.sh and make its first line #!/usr/bin/env bash↑↓
2. 2. Put these lines of a file-reading loop in the order they must appear in the script.

   Use the arrows to put the steps in order.

   1. 1.done < fruit.txt↑↓
   2. 2.while IFS= read -r line; do↑↓
   3. 3.echo "line: $line"↑↓
3. 3. Put these steps in the order they happen when an if test uses grep -q.

   Use the arrows to put the steps in order.

   1. 1.The if reads exit code 0 as a true test↑↓
   2. 2.The then block runs and prints found banana↑↓
   3. 3.grep finds a match and exits with code 0↑↓
   4. 4.grep -q banana fruit.txt searches the file and prints nothing↑↓
4. 4. This script should print hello Asha. What is wrong with it? ``bash #!/usr/bin/env bash name = "Asha" echo "hello $name" ``

   Nothing is wrong, because bash allows spaces around the = signThe echo line needs single quotes around the textThe spaces around = make bash read name as a command, so the variable is never setThe first line must be #!/bin/sh for variables to work
5. 5. This script is meant to say found when the file my notes.txt exists. Run it and it prints an error line before no. ``bash #!/usr/bin/env bash f="my notes.txt" if [ -f $f ]; then echo found; else echo no; fi `` What is the bug?

   The -f test checks for folders, so it should be -dThe then keyword is missing a semicolon before itThe name my notes.txt has a space, so the file can never be foundThe variable is not in double quotes, so the name splits into two words and the test fails with an error